1.21-0.25x^2=0

Solution for 1.21-0.25x^2=0 equation:

1.21-0.25x^2=0

a = -0.25; b = 0; c = +1.21;
Δ = b2-4ac
Δ = 02-4·(-0.25)·1.21
Δ = 1.21
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{1.21}}{2*-0.25}=\frac{0-\sqrt{1.21}}{-0.5}
=-\frac{\sqrt{}}{-0.5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{1.21}}{2*-0.25}=\frac{0+\sqrt{1.21}}{-0.5}
=\frac{\sqrt{}}{-0.5}
$